What is the vertices 16x^2+25y^2+64x-200y+64=0 ?

The vertices 16x^2+25y^2+64x-200y+64=0 is (3,4),(-7,4)

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vertices 16x^2+25y^2+64x-200y+64=0

vertices

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0

(3, 4), (- 7, 4)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0 :

Ellipse with center

(h, k) = (- 2, 4), a = 5, b = 4

(- 2 + 5, 4), (- 2 - 5, 4)

Refine

(3, 4), (- 7, 4)

2 x^{2} + y^{2} = 4

9 x^{2} + 4 y^{2} - 18 x - 16 y - 11 = 0

4 x^{2} + 9 y^{2} = 25

\frac{( x + 3 ) ^{2}}{26} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

What is the vertices 16x^2+25y^2+64x-200y+64=0 ?
The vertices 16x^2+25y^2+64x-200y+64=0 is (3,4),(-7,4)