en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x^2+16y^2=16

Solution

vertices

x^{2} + 16 y^{2} = 16

Solution

(4, 0), (- 4, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 16 y^{2} = 16 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 1

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

Popular Examples

vertices ((x+3)^2)/4+((y-2)^2)/(16)=1 vertices

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1

vertices (x^2}{49}+\frac{y^2)/9 =1 vertices

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

vertices ((x-5)^2)/9+((y-3)^2)/(16)=1 vertices

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{16} = 1

vertices x^2+9y^2=36 vertices

x^{2} + 9 y^{2} = 36

vertices (x^2)/(121)+(y/1)^2=1 vertices

\frac{x ^{2}}{121} + (\frac{y}{1})^{2} = 1

Frequently Asked Questions (FAQ)

What is the vertices x^2+16y^2=16 ?
The vertices x^2+16y^2=16 is (4,0),(-4,0)