What is the vertices (x^2)/(12)+(y^2)/(144)= y/(12) ?

The vertices (x^2)/(12)+(y^2)/(144)= y/(12) is (0,12),(0,0)

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vertices (x^2)/(12)+(y^2)/(144)= y/(12)

vertices

\frac{x ^{2}}{12} + \frac{y ^{2}}{144} = \frac{y}{12}

(0, 12), (0, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{12} + \frac{y ^{2}}{144} = \frac{y}{12} :

Ellipse with center

(h, k) = (0, 6), b = 6, a = 3

(0, 6 + 6), (0, 6 - 6)

Refine

(0, 12), (0, 0)

81 x^{2} + 36 y^{2} = 2916

(x)^{2} + \frac{( y - 1 ) ^{2}}{4} = 1

16 (x - 1)^{2} + 25 (y - 4)^{2} = 400

25 x^{2} + 16 y^{2} - 50 x + 64 y - 311 = 0

16 x^{2} + 36 y^{2} - 256 x + 448 = 0

What is the vertices (x^2)/(12)+(y^2)/(144)= y/(12) ?
The vertices (x^2)/(12)+(y^2)/(144)= y/(12) is (0,12),(0,0)