What is the vertices 9x^2+y^2-18x-6y+9=0 ?

The vertices 9x^2+y^2-18x-6y+9=0 is (1,6),(1,0)

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vertices 9x^2+y^2-18x-6y+9=0

vertices

9 x^{2} + y^{2} - 18 x - 6 y + 9 = 0

(1, 6), (1, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + y^{2} - 18 x - 6 y + 9 = 0 :

Ellipse with center

(h, k) = (1, 3), b = 3, a = 1

(1, 3 + 3), (1, 3 - 3)

Refine

(1, 6), (1, 0)

\frac{( x - 0 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{49} = 1

81 x^{2} + 64 y^{2} = 5184

16 x^{2} + 25 y^{2} - 64 x + 150 y = - 279

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{5} = 1

2 x^{2} + 3 y^{2} + 4 x - 1 = 0

What is the vertices 9x^2+y^2-18x-6y+9=0 ?
The vertices 9x^2+y^2-18x-6y+9=0 is (1,6),(1,0)