What is the vertices 81x^2+64y^2=5184 ?

The vertices 81x^2+64y^2=5184 is (0,9),(0,-9)

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vertices 81x^2+64y^2=5184

vertices

81 x^{2} + 64 y^{2} = 5184

(0, 9), (0, - 9)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

81 x^{2} + 64 y^{2} = 5184 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 8

(0, 0 + 9), (0, 0 - 9)

Refine

(0, 9), (0, - 9)

16 x^{2} + 25 y^{2} - 64 x + 150 y = - 279

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{5} = 1

2 x^{2} + 3 y^{2} + 4 x - 1 = 0

25 x^{2} + 9 y^{2} + 200 x - 90 y + 400 = 0

9 x^{2} + 36 y^{2} + 36 x - 216 y + 36 = 0

What is the vertices 81x^2+64y^2=5184 ?
The vertices 81x^2+64y^2=5184 is (0,9),(0,-9)