What is the foci (y^2}{25}+\frac{x^2)/9 =1 ?

The foci (y^2}{25}+\frac{x^2)/9 =1 is (0,4),(0,-4)

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foci (y^2}{25}+\frac{x^2)/9 =1

foci

\frac{y ^{2}}{25} + \frac{x ^{2}}{9} = 1

(0, 4), (0, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{y ^{2}}{25} + \frac{x ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 3^{2} : 4

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

4 x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

9 x^{2} - 36 x + 4 y^{2} = 0

x^{2} + 4 y^{2} = 4

25 x^{2} + 16 y^{2} + 50 x - 64 y - 311 = 0

x^{2} + 8 (y + 5)^{2} = 20

What is the foci (y^2}{25}+\frac{x^2)/9 =1 ?
The foci (y^2}{25}+\frac{x^2)/9 =1 is (0,4),(0,-4)