What is the foci (x^2)/(81)+(y^2)/(16)=1 ?

The foci (x^2)/(81)+(y^2)/(16)=1 is (sqrt(65),0),(-sqrt(65),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(81)+(y^2)/(16)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{16} = 1

(65, 0), (- 65, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 4^{2} : 65

(0 + 65, 0), (0 - 65, 0)

Refine

(65, 0), (- 65, 0)

9 x^{2} + 16 y^{2} + 126 x + 96 y + 441 = 0

\frac{( x - 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{9} = 3

8 x^{2} + 2 y^{2} + 16 x = 0

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

16 x^{2} + 25 y^{2} - 64 x - 50 y - 311 = 0

What is the foci (x^2)/(81)+(y^2)/(16)=1 ?
The foci (x^2)/(81)+(y^2)/(16)=1 is (sqrt(65),0),(-sqrt(65),0)