What is the foci (x^2)/(169)+(y^2)/(144)=1 ?

The foci (x^2)/(169)+(y^2)/(144)=1 is (5,0),(-5,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(169)+(y^2)/(144)=1

foci

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{169} + \frac{y ^{2}}{144} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 13, b = 12

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 3^{2} - 1 2^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

16 x^{2} + 25 y^{2} - 64 x - 50 y - 311 = 0

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{3} + \frac{y ^{2}}{2} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

What is the foci (x^2)/(169)+(y^2)/(144)=1 ?
The foci (x^2)/(169)+(y^2)/(144)=1 is (5,0),(-5,0)