What is the foci (x^2)/3+(y^2)/2 =1 ?

The foci (x^2)/3+(y^2)/2 =1 is (1,0),(-1,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/3+(y^2)/2 =1

foci

\frac{x ^{2}}{3} + \frac{y ^{2}}{2} = 1

(1, 0), (- 1, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{3} + \frac{y ^{2}}{2} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 3, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} - 2^{2} : 1

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

\frac{( x - 4 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

\frac{( x + 1 ) ^{2}}{28} + \frac{( y + 5 ) ^{2}}{23} = 1

What is the foci (x^2)/3+(y^2)/2 =1 ?
The foci (x^2)/3+(y^2)/2 =1 is (1,0),(-1,0)