What is the foci (x^2)/(256)+(y^2)/(400)=1 ?

The foci (x^2)/(256)+(y^2)/(400)=1 is (0,12),(0,-12)

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foci (x^2)/(256)+(y^2)/(400)=1

foci

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1

(0, 12), (0, - 12)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 20, a = 16

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2 0^{2} - 1 6^{2} : 12

(0, 0 + 12), (0, 0 - 12)

Refine

(0, 12), (0, - 12)

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

25 x^{2} + 16 y^{2} = 400

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{16} = 1

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

\frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1

What is the foci (x^2)/(256)+(y^2)/(400)=1 ?
The foci (x^2)/(256)+(y^2)/(400)=1 is (0,12),(0,-12)