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Popular >

foci 25x^2+16y^2=400

Solution

foci

25 x^{2} + 16 y^{2} = 400

Solution

(0, 3), (0, - 3)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 16 y^{2} = 400 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 4^{2} : 3

(0, 0 + 3), (0, 0 - 3)

Refine

(0, 3), (0, - 3)

Popular Examples

foci ((x-3)^2)/(25)+((y+1)^2)/(16)=1 foci

\frac{( x - 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{16} = 1

foci 2x^2+y^2+12x-6y+26=0 foci

2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

foci ((x-h)^2)/(a^2)+((y-k)^2)/(b^2)=1 foci

\frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1

foci ((x-3)^2)/(49)+((y+5)^2)/(25)=1 foci

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{25} = 1

foci (x^2)/8+(y^2)/4 =1 foci

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is the foci 25x^2+16y^2=400 ?
The foci 25x^2+16y^2=400 is (0,3),(0,-3)