What is the foci (x^2)/8+(y^2)/4 =1 ?

The foci (x^2)/8+(y^2)/4 =1 is (2,0),(-2,0)

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foci (x^2)/8+(y^2)/4 =1

foci

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

(2, 0), (- 2, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 22, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (22)^{2} - 2^{2} : 2

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

9 x^{2} + 16 y^{2} = 576

3 x^{2} + y^{2} + 2 x - 6 y = 3

9 x^{2} + 25 y^{2} + 18 x + 150 y + 9 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{49} = 1

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

What is the foci (x^2)/8+(y^2)/4 =1 ?
The foci (x^2)/8+(y^2)/4 =1 is (2,0),(-2,0)