What is the foci 9x^2+16y^2=576 ?

The foci 9x^2+16y^2=576 is (2sqrt(7),0),(-2sqrt(7),0)

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foci 9x^2+16y^2=576

foci

9 x^{2} + 16 y^{2} = 576

(27, 0), (- 27, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 16 y^{2} = 576 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 6^{2} : 27

(0 + 27, 0), (0 - 27, 0)

Refine

(27, 0), (- 27, 0)

3 x^{2} + y^{2} + 2 x - 6 y = 3

9 x^{2} + 25 y^{2} + 18 x + 150 y + 9 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{49} = 1

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

x^{2} + y^{2} + 2 x = 3 y

What is the foci 9x^2+16y^2=576 ?
The foci 9x^2+16y^2=576 is (2sqrt(7),0),(-2sqrt(7),0)