What is the foci 4x^2+9y^2-8x-36y+4=0 ?

The foci 4x^2+9y^2-8x-36y+4=0 is (1+sqrt(5),2),(1-sqrt(5),2)

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foci 4x^2+9y^2-8x-36y+4=0

foci

4 x^{2} + 9 y^{2} - 8 x - 36 y + 4 = 0

(1 + 5, 2), (1 - 5, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} - 8 x - 36 y + 4 = 0 :

Ellipse with center

(h, k) = (1, 2), a = 3, b = 2

(1 + c, 2), (1 - c, 2)

Compute

c :

c = 3^{2} - 2^{2} : 5

(1 + 5, 2), (1 - 5, 2)

16 x^{2} + 25 y^{2} + 32 x - 384 = 0

3 x^{2} + 7 y^{2} - 12 x - 28 y + 19 = 0

x^{2} + 10 x + 9 y^{2} + 16 = 0

9 x^{2} + y^{2} + 18 x + 4 y + 4 = 0

5 x^{2} + 2 y^{2} = 50

What is the foci 4x^2+9y^2-8x-36y+4=0 ?
The foci 4x^2+9y^2-8x-36y+4=0 is (1+sqrt(5),2),(1-sqrt(5),2)