What is the foci 9x^2+y^2+18x+4y+4=0 ?

The foci 9x^2+y^2+18x+4y+4=0 is (-1,-2+2sqrt(2)),(-1,-2-2sqrt(2))

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foci 9x^2+y^2+18x+4y+4=0

foci

9 x^{2} + y^{2} + 18 x + 4 y + 4 = 0

(- 1, - 2 + 22), (- 1, - 2 - 22)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

9 x^{2} + y^{2} + 18 x + 4 y + 4 = 0 :

Ellipse with center

(h, k) = (- 1, - 2), b = 3, a = 1

(- 1, - 2 + c), (- 1, - 2 - c)

Compute

c :

c = 3^{2} - 1^{2} : 22

(- 1, - 2 + 22), (- 1, - 2 - 22)

5 x^{2} + 2 y^{2} = 50

4 x^{2} + 49 y^{2} = 196

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

16 x^{2} - 96 x + 4 y^{2} = - 80

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

What is the foci 9x^2+y^2+18x+4y+4=0 ?
The foci 9x^2+y^2+18x+4y+4=0 is (-1,-2+2sqrt(2)),(-1,-2-2sqrt(2))