What is the foci 9x^2+25y^2+36x+250y=-436 ?

The foci 9x^2+25y^2+36x+250y=-436 is (2,-5),(-6,-5)

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foci 9x^2+25y^2+36x+250y=-436

foci

9 x^{2} + 25 y^{2} + 36 x + 250 y = - 436

(2, - 5), (- 6, - 5)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 36 x + 250 y = - 436 :

Ellipse with center

(h, k) = (- 2, - 5), a = 5, b = 3

(- 2 + c, - 5), (- 2 - c, - 5)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 2 + 4, - 5), (- 2 - 4, - 5)

Refine

(2, - 5), (- 6, - 5)

\frac{x ^{2}}{2} + \frac{y ^{2}}{4} = 1

x^{2} + \frac{y ^{2}}{4} = 1

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

\frac{x ^{2}}{4} + y^{2} = 1

x^{2} + \frac{1}{3} y^{2} = x + y

What is the foci 9x^2+25y^2+36x+250y=-436 ?
The foci 9x^2+25y^2+36x+250y=-436 is (2,-5),(-6,-5)