What is the foci 25x^2+4y^2=100 ?

The foci 25x^2+4y^2=100 is (0,sqrt(21)),(0,-sqrt(21))

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foci 25x^2+4y^2=100

foci

25 x^{2} + 4 y^{2} = 100

(0, 21), (0, - 21)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 4 y^{2} = 100 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 2^{2} : 21

(0, 0 + 21), (0, 0 - 21)

Refine

(0, 21), (0, - 21)

9 x^{2} + 36 y^{2} + 36 x + 432 y = - 1008

4 x^{2} + 9 y^{2} - 32 x - 36 y + 64 = 0

4 x^{2} + y^{2} = 4

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{4} = 1

What is the foci 25x^2+4y^2=100 ?
The foci 25x^2+4y^2=100 is (0,sqrt(21)),(0,-sqrt(21))