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Popular >

foci 5x^2+2y^2=10

Solution

foci

5 x^{2} + 2 y^{2} = 10

Solution

(0, 3), (0, - 3)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

5 x^{2} + 2 y^{2} = 10 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 2^{2} : 3

(0, 0 + 3), (0, 0 - 3)

Refine

(0, 3), (0, - 3)

Popular Examples

foci (x^2)/(36)+(y^2)/(81)=1 foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{81} = 1

foci (y^2)/(81)+(x^2)/(36)=1 foci

\frac{y ^{2}}{81} + \frac{x ^{2}}{36} = 1

foci ((x+4)^2)/(16)+((y-1)^2)/(36)=1 foci

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{36} = 1

foci 16x^2+25y^2+100y-300=0 foci

16 x^{2} + 25 y^{2} + 100 y - 300 = 0

foci (x^2)/(8^2)+(y^2)/(4^2)=1 foci

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

Frequently Asked Questions (FAQ)

What is the foci 5x^2+2y^2=10 ?
The foci 5x^2+2y^2=10 is (0,sqrt(3)),(0,-sqrt(3))