What is the foci (x^2)/(8^2)+(y^2)/(4^2)=1 ?

The foci (x^2)/(8^2)+(y^2)/(4^2)=1 is (4sqrt(3),0),(-4sqrt(3),0)

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foci (x^2)/(8^2)+(y^2)/(4^2)=1

foci

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

(43, 0), (- 43, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 4^{2} : 43

(0 + 43, 0), (0 - 43, 0)

Refine

(43, 0), (- 43, 0)

x^{2} + 3 y^{2} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{36} = 1

\frac{( x - 4 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

\frac{( x - 6 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{25} = 1

What is the foci (x^2)/(8^2)+(y^2)/(4^2)=1 ?
The foci (x^2)/(8^2)+(y^2)/(4^2)=1 is (4sqrt(3),0),(-4sqrt(3),0)