What is the foci 4(x-1)^2+9(y-1)^2=36 ?

The foci 4(x-1)^2+9(y-1)^2=36 is (1+sqrt(5),1),(1-sqrt(5),1)

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foci 4(x-1)^2+9(y-1)^2=36

foci

4 (x - 1)^{2} + 9 (y - 1)^{2} = 36

(1 + 5, 1), (1 - 5, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 (x - 1)^{2} + 9 (y - 1)^{2} = 36 :

Ellipse with center

(h, k) = (1, 1), a = 3, b = 2

(1 + c, 1), (1 - c, 1)

Compute

c :

c = 3^{2} - 2^{2} : 5

(1 + 5, 1), (1 - 5, 1)

\frac{( x + 1 ) ^{2}}{100} + \frac{( y + 2 ) ^{2}}{121} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

\frac{( x - 4 ) ^{2}}{24} + \frac{( y - 2 ) ^{2}}{49} = 1

x^{2} + 2 y^{2} + 2 x - 8 y + 7 = 0

\frac{( x + 13 ) ^{2}}{400} + \frac{( y + 6 ) ^{2}}{625} = 1

What is the foci 4(x-1)^2+9(y-1)^2=36 ?
The foci 4(x-1)^2+9(y-1)^2=36 is (1+sqrt(5),1),(1-sqrt(5),1)