What is the foci ((x+13)^2)/(400)+((y+6)^2)/(625)=1 ?

The foci ((x+13)^2)/(400)+((y+6)^2)/(625)=1 is (-13,9),(-13,-21)

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foci ((x+13)^2)/(400)+((y+6)^2)/(625)=1

foci

\frac{( x + 13 ) ^{2}}{400} + \frac{( y + 6 ) ^{2}}{625} = 1

(- 13, 9), (- 13, - 21)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{( x + 13 ) ^{2}}{400} + \frac{( y + 6 ) ^{2}}{625} = 1 :

Ellipse with center

(h, k) = (- 13, - 6), b = 25, a = 20

(- 13, - 6 + c), (- 13, - 6 - c)

Compute

c :

c = 2 5^{2} - 2 0^{2} : 15

(- 13, - 6 + 15), (- 13, - 6 - 15)

Refine

(- 13, 9), (- 13, - 21)

4 x^{2} + y^{2} - 16 x - 2 y - 19 = 0

\frac{x ^{2}}{4} + (y - 1)^{2} = 1

3 x^{2} + 7 y^{2} = 63

25 x^{2} + 9 y^{2} = 225

\frac{x ^{2}}{34} + \frac{y ^{2}}{9} = 1

What is the foci ((x+13)^2)/(400)+((y+6)^2)/(625)=1 ?
The foci ((x+13)^2)/(400)+((y+6)^2)/(625)=1 is (-13,9),(-13,-21)