What is the foci ((x^2)/(15))+((y^2)/(16))=1 ?

The foci ((x^2)/(15))+((y^2)/(16))=1 is (0,1),(0,-1)

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foci ((x^2)/(15))+((y^2)/(16))=1

foci

(\frac{x ^{2}}{15}) + (\frac{y ^{2}}{16}) = 1

(0, 1), (0, - 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{15} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 15

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} - 15^{2} : 1

(0, 0 + 1), (0, 0 - 1)

Refine

(0, 1), (0, - 1)

9 x^{2} - 18 x + 25 y^{2} - 250 y + 409 = 0

25 x^{2} + 9 y^{2} + 50 x - 108 y + 124 = 0

x^{2} + 2 y^{2} = 4

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

16 x^{2} + 25 y^{2} - 64 x + 150 y - 111 = 0

What is the foci ((x^2)/(15))+((y^2)/(16))=1 ?
The foci ((x^2)/(15))+((y^2)/(16))=1 is (0,1),(0,-1)