What is the foci 16x^2+25y^2-64x+150y-111=0 ?

The foci 16x^2+25y^2-64x+150y-111=0 is (5,-3),(-1,-3)

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foci 16x^2+25y^2-64x+150y-111=0

foci

16 x^{2} + 25 y^{2} - 64 x + 150 y - 111 = 0

(5, - 3), (- 1, - 3)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} - 64 x + 150 y - 111 = 0 :

Ellipse with center

(h, k) = (2, - 3), a = 5, b = 4

(2 + c, - 3), (2 - c, - 3)

Compute

c :

c = 5^{2} - 4^{2} : 3

(2 + 3, - 3), (2 - 3, - 3)

Refine

(5, - 3), (- 1, - 3)

9 x^{2} + 49 y^{2} = 441

\frac{( x - 1 ) ^{2}}{425} + \frac{( y - 2 ) ^{2}}{400} = 1

9 x^{2} + 4 y^{2} + 18 x - 8 y - 131 = 0

\frac{( x - 2 ) ^{2}}{225} + \frac{( y - 8 ) ^{2}}{81} = 1

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

What is the foci 16x^2+25y^2-64x+150y-111=0 ?
The foci 16x^2+25y^2-64x+150y-111=0 is (5,-3),(-1,-3)