What is the foci ((x-2)^2)/(225)+((y-8)^2)/(81)=1 ?

The foci ((x-2)^2)/(225)+((y-8)^2)/(81)=1 is (14,8),(-10,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((x-2)^2)/(225)+((y-8)^2)/(81)=1

foci

\frac{( x - 2 ) ^{2}}{225} + \frac{( y - 8 ) ^{2}}{81} = 1

(14, 8), (- 10, 8)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 2 ) ^{2}}{225} + \frac{( y - 8 ) ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (2, 8), a = 15, b = 9

(2 + c, 8), (2 - c, 8)

Compute

c :

c = 1 5^{2} - 9^{2} : 12

(2 + 12, 8), (2 - 12, 8)

Refine

(14, 8), (- 10, 8)

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

2 x^{2} + 3 y^{2} + 10 x + 10 y - 10 = 0

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 6 ) ^{2}}{4} = 1

\frac{x ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

What is the foci ((x-2)^2)/(225)+((y-8)^2)/(81)=1 ?
The foci ((x-2)^2)/(225)+((y-8)^2)/(81)=1 is (14,8),(-10,8)