What is the foci (x^2)/4+(y^2)/3 =1 ?

The foci (x^2)/4+(y^2)/3 =1 is (1,0),(-1,0)

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foci (x^2)/4+(y^2)/3 =1

foci

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

(1, 0), (- 1, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} - 3^{2} : 1

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

2 x^{2} + 3 y^{2} + 10 x + 10 y - 10 = 0

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 6 ) ^{2}}{4} = 1

\frac{x ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

\frac{( x + 4 ) ^{2}}{225} + \frac{( y - 7 ) ^{2}}{81} = 1

9 x^{2} + 4 y^{2} = 24 y

What is the foci (x^2)/4+(y^2)/3 =1 ?
The foci (x^2)/4+(y^2)/3 =1 is (1,0),(-1,0)