What is the foci ((x+4)^2)/(225)+((y-7)^2)/(81)=1 ?

The foci ((x+4)^2)/(225)+((y-7)^2)/(81)=1 is (8,7),(-16,7)

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foci ((x+4)^2)/(225)+((y-7)^2)/(81)=1

foci

\frac{( x + 4 ) ^{2}}{225} + \frac{( y - 7 ) ^{2}}{81} = 1

(8, 7), (- 16, 7)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 4 ) ^{2}}{225} + \frac{( y - 7 ) ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (- 4, 7), a = 15, b = 9

(- 4 + c, 7), (- 4 - c, 7)

Compute

c :

c = 1 5^{2} - 9^{2} : 12

(- 4 + 12, 7), (- 4 - 12, 7)

Refine

(8, 7), (- 16, 7)

9 x^{2} + 4 y^{2} = 24 y

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

2 x^{2} + 4 y^{2} - 8 x - 4 y - 15 = 0

3 x^{2} + y^{2} = 9

16 x^{2} + 81 y^{2} = 81

What is the foci ((x+4)^2)/(225)+((y-7)^2)/(81)=1 ?
The foci ((x+4)^2)/(225)+((y-7)^2)/(81)=1 is (8,7),(-16,7)