What is the foci 25x^2+36y^2=900 ?

The foci 25x^2+36y^2=900 is (sqrt(11),0),(-sqrt(11),0)

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foci 25x^2+36y^2=900

foci

25 x^{2} + 36 y^{2} = 900

(11, 0), (- 11, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

25 x^{2} + 36 y^{2} = 900 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} - 5^{2} : 11

(0 + 11, 0), (0 - 11, 0)

Refine

(11, 0), (- 11, 0)

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{5} = 1

4 x^{2} + 25 y^{2} - 50 y = 75

x^{2} + 4 y^{2} - 16 = 0

16 (x - 1)^{2} + 9 (y + 2)^{2} = 144

What is the foci 25x^2+36y^2=900 ?
The foci 25x^2+36y^2=900 is (sqrt(11),0),(-sqrt(11),0)