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Popular >

foci x^2+4y^2-16=0

Solution

foci

x^{2} + 4 y^{2} - 16 = 0

Solution

(23, 0), (- 23, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

x^{2} + 4 y^{2} - 16 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} - 2^{2} : 23

(0 + 23, 0), (0 - 23, 0)

Refine

(23, 0), (- 23, 0)

Popular Examples

foci 16(x-1)^2+9(y+2)^2=144 foci

16 (x - 1)^{2} + 9 (y + 2)^{2} = 144

foci ((x-5)^2)/3+((y-7)^2)/6 =1 foci

\frac{( x - 5 ) ^{2}}{3} + \frac{( y - 7 ) ^{2}}{6} = 1

foci (x^2)/(100)+(y^2)/(50)=1 foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{50} = 1

foci (x^2)/(49)+(y^2)/(81)=1 foci

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1

foci 25x^2+16y^2+100x+96y-156=0 foci

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0

Frequently Asked Questions (FAQ)

What is the foci x^2+4y^2-16=0 ?
The foci x^2+4y^2-16=0 is (2sqrt(3),0),(-2sqrt(3),0)