What is the foci 9x^2+9y^2+18x-18y+14=0 ?

The foci 9x^2+9y^2+18x-18y+14=0 is (-1,1),(-1,1)

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foci 9x^2+9y^2+18x-18y+14=0

foci

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

(- 1, 1), (- 1, 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0 :

Ellipse with center

(h, k) = (- 1, 1), b = \frac{2}{3}, a = \frac{2}{3}

(- 1, 1 + c), (- 1, 1 - c)

Compute

c :

c = (\frac{2}{3})^{2} - (\frac{2}{3})^{2} : 0

(- 1, 1 + 0), (- 1, 1 - 0)

Refine

(- 1, 1), (- 1, 1)

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

\frac{( x - 2 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

36 x^{2} + 9 y^{2} + 48 x - 36 y + 43 = 0

4 x^{2} + 9 y^{2} - 18 y - 27 = 0

9 x^{2} + 36 x + y^{2} + 2 y + 36 = 0

What is the foci 9x^2+9y^2+18x-18y+14=0 ?
The foci 9x^2+9y^2+18x-18y+14=0 is (-1,1),(-1,1)