What is the foci ((x-1)^2)/3+((y-2)^2)/4 =1 ?

The foci ((x-1)^2)/3+((y-2)^2)/4 =1 is (1,3),(1,1)

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foci ((x-1)^2)/3+((y-2)^2)/4 =1

foci

\frac{( x - 1 ) ^{2}}{3} + \frac{( y - 2 ) ^{2}}{4} = 1

(1, 3), (1, 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{( x - 1 ) ^{2}}{3} + \frac{( y - 2 ) ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (1, 2), b = 2, a = 3

(1, 2 + c), (1, 2 - c)

Compute

c :

c = 2^{2} - 3^{2} : 1

(1, 2 + 1), (1, 2 - 1)

Refine

(1, 3), (1, 1)

x^{2} + 4 y^{2} = 36

81 x^{2} + 9 y^{2} = 9

\frac{x ^{2}}{16} + \frac{( y - 4 ) ^{2}}{1} = 1

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 6 ) ^{2}}{121} = 1

\frac{( x + 7 ) ^{2}}{8} + \frac{( y - 10 ) ^{2}}{13} = 1

What is the foci ((x-1)^2)/3+((y-2)^2)/4 =1 ?
The foci ((x-1)^2)/3+((y-2)^2)/4 =1 is (1,3),(1,1)