What is the foci (x^2)/(64)+(y^2)/(15)=1 ?

The foci (x^2)/(64)+(y^2)/(15)=1 is (7,0),(-7,0)

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foci (x^2)/(64)+(y^2)/(15)=1

foci

\frac{x ^{2}}{64} + \frac{y ^{2}}{15} = 1

(7, 0), (- 7, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{64} + \frac{y ^{2}}{15} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 15

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 15^{2} : 7

(0 + 7, 0), (0 - 7, 0)

Refine

(7, 0), (- 7, 0)

4 x^{2} + 24 x + 25 y^{2} + 200 y + 336 = 0

\frac{( x + 1 ) ^{2}}{10} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x ) ^{2}}{44} + \frac{y ^{2}}{125} = 1

2 x^{2} + 8 y^{2} = 16

64 x^{2} + y^{2} = 64

What is the foci (x^2)/(64)+(y^2)/(15)=1 ?
The foci (x^2)/(64)+(y^2)/(15)=1 is (7,0),(-7,0)