What is the foci (x^2)/(36)+(y^2)/(64)=1 ?

The foci (x^2)/(36)+(y^2)/(64)=1 is (0,2sqrt(7)),(0,-2sqrt(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(36)+(y^2)/(64)=1

foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{64} = 1

(0, 27), (0, - 27)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{36} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} - 6^{2} : 27

(0, 0 + 27), (0, 0 - 27)

Refine

(0, 27), (0, - 27)

\frac{x ^{2}}{16} + y^{2} = 1

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

\frac{( y + 3 ) ^{2}}{144} + \frac{( x + 2 ) ^{2}}{25} = 1

What is the foci (x^2)/(36)+(y^2)/(64)=1 ?
The foci (x^2)/(36)+(y^2)/(64)=1 is (0,2sqrt(7)),(0,-2sqrt(7))