What is the foci 9x^2+16y^2+96y=0 ?

The foci 9x^2+16y^2+96y=0 is (sqrt(7),-3),(-sqrt(7),-3)

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foci 9x^2+16y^2+96y=0

foci

9 x^{2} + 16 y^{2} + 96 y = 0

(7, - 3), (- 7, - 3)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 16 y^{2} + 96 y = 0 :

Ellipse with center

(h, k) = (0, - 3), a = 4, b = 3

(0 + c, - 3), (0 - c, - 3)

Compute

c :

c = 4^{2} - 3^{2} : 7

(0 + 7, - 3), (0 - 7, - 3)

Refine

(7, - 3), (- 7, - 3)

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

\frac{x ^{2}}{99} + \frac{y ^{2}}{225} = 1

4 x^{2} + 9 y^{2} = 1

25 x^{2} + 16 y^{2} - 100 x - 300 = 0

\frac{( x - 2 ) ^{2}}{2} + \frac{( y - 1 ) ^{2}}{8} = 1

What is the foci 9x^2+16y^2+96y=0 ?
The foci 9x^2+16y^2+96y=0 is (sqrt(7),-3),(-sqrt(7),-3)