What is the foci (x^2)/(15)+(y^2)/(64)=1 ?

The foci (x^2)/(15)+(y^2)/(64)=1 is (0,7),(0,-7)

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foci (x^2)/(15)+(y^2)/(64)=1

foci

\frac{x ^{2}}{15} + \frac{y ^{2}}{64} = 1

(0, 7), (0, - 7)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{15} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 15

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} - 15^{2} : 7

(0, 0 + 7), (0, 0 - 7)

Refine

(0, 7), (0, - 7)

25 x^{2} + 9 y^{2} - 150 x - 18 y + 9 = 0

\frac{x ^{2}}{64} + \frac{y ^{2}}{4} = 1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 5 ) ^{2}}{25} = 1

16 x^{2} + 64 x + 4 y^{2} - 8 y + 4 = 0

\frac{x ^{2}}{17} + \frac{y ^{2}}{35} = 1

What is the foci (x^2)/(15)+(y^2)/(64)=1 ?
The foci (x^2)/(15)+(y^2)/(64)=1 is (0,7),(0,-7)