What is the foci (x^2}{64}+\frac{y^2)/4 =1 ?

The foci (x^2}{64}+\frac{y^2)/4 =1 is (2sqrt(15),0),(-2sqrt(15),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2}{64}+\frac{y^2)/4 =1

foci

\frac{x ^{2}}{64} + \frac{y ^{2}}{4} = 1

(215, 0), (- 215, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{64} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 2^{2} : 215

(0 + 215, 0), (0 - 215, 0)

Refine

(215, 0), (- 215, 0)

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 5 ) ^{2}}{25} = 1

16 x^{2} + 64 x + 4 y^{2} - 8 y + 4 = 0

\frac{x ^{2}}{17} + \frac{y ^{2}}{35} = 1

64 x^{2} + 81 y^{2} = 5184

\frac{( x ) ^{2}}{9} + \frac{y ^{2}}{4} = 1

What is the foci (x^2}{64}+\frac{y^2)/4 =1 ?
The foci (x^2}{64}+\frac{y^2)/4 =1 is (2sqrt(15),0),(-2sqrt(15),0)