What is the foci 64x^2+81y^2=5184 ?

The foci 64x^2+81y^2=5184 is (sqrt(17),0),(-sqrt(17),0)

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foci 64x^2+81y^2=5184

foci

64 x^{2} + 81 y^{2} = 5184

(17, 0), (- 17, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

64 x^{2} + 81 y^{2} = 5184 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 8^{2} : 17

(0 + 17, 0), (0 - 17, 0)

Refine

(17, 0), (- 17, 0)

\frac{( x ) ^{2}}{9} + \frac{y ^{2}}{4} = 1

4 x^{2} + y^{2} + 40 x + 6 y + 95 = 0

\frac{x ^{2}}{1} + \frac{y ^{2}}{4} = 1

\frac{( y + 4 ) ^{2}}{24} + \frac{( x - 3 ) ^{2}}{12} = 1

4 x^{2} + 16 y^{2} - 64 = 0

What is the foci 64x^2+81y^2=5184 ?
The foci 64x^2+81y^2=5184 is (sqrt(17),0),(-sqrt(17),0)