What is the foci 4x^2+36y^2=144 ?

The foci 4x^2+36y^2=144 is (4sqrt(2),0),(-4sqrt(2),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 4x^2+36y^2=144

foci

4 x^{2} + 36 y^{2} = 144

(42, 0), (- 42, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 36 y^{2} = 144 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} - 2^{2} : 42

(0 + 42, 0), (0 - 42, 0)

Refine

(42, 0), (- 42, 0)

\frac{( x ) ^{2}}{25} + \frac{( y ) ^{2}}{9} = 1

1 x^{2} + 4 y^{2} + 10 x + 9 y - 10 = 0

\frac{( x + 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{25} = 1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

x^{2} + 16 y^{2} - 64 = 0

What is the foci 4x^2+36y^2=144 ?
The foci 4x^2+36y^2=144 is (4sqrt(2),0),(-4sqrt(2),0)