What is the foci 16x^2+25y^2-64x-336=0 ?

The foci 16x^2+25y^2-64x-336=0 is (5,0),(-1,0)

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foci 16x^2+25y^2-64x-336=0

foci

16 x^{2} + 25 y^{2} - 64 x - 336 = 0

(5, 0), (- 1, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} - 64 x - 336 = 0 :

Ellipse with center

(h, k) = (2, 0), a = 5, b = 4

(2 + c, 0), (2 - c, 0)

Compute

c :

c = 5^{2} - 4^{2} : 3

(2 + 3, 0), (2 - 3, 0)

Refine

(5, 0), (- 1, 0)

\frac{( x ) ^{2}}{25} + \frac{y ^{2}}{16} = 1

x^{2} + 4 y^{2} - 64 = 0

4 (x + 2)^{2} + 16 (y - 2)^{2} = 64

\frac{( x - 7 ) ^{2}}{64} + \frac{( y + 2 ) ^{2}}{25} = 1

\frac{( x - 4 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{1} = 1

What is the foci 16x^2+25y^2-64x-336=0 ?
The foci 16x^2+25y^2-64x-336=0 is (5,0),(-1,0)