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Popular >

foci x^2+4y^2-64=0

Solution

foci

x^{2} + 4 y^{2} - 64 = 0

Solution

(43, 0), (- 43, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

x^{2} + 4 y^{2} - 64 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} - 4^{2} : 43

(0 + 43, 0), (0 - 43, 0)

Refine

(43, 0), (- 43, 0)

Popular Examples

foci 4(x+2)^2+16(y-2)^2=64 foci

4 (x + 2)^{2} + 16 (y - 2)^{2} = 64

foci ((x-7)^2)/(64)+((y+2)^2)/(25)=1 foci

\frac{( x - 7 ) ^{2}}{64} + \frac{( y + 2 ) ^{2}}{25} = 1

foci ((x-4)^2}{25}+\frac{(y-2)^2)/1 =1 foci

\frac{( x - 4 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{1} = 1

foci ((x-1)^2+(y-3)^2)/2 =1 foci

\frac{( x - 1 ) ^{2} + ( y - 3 ) ^{2}}{2} = 1

foci (x^2)/(289)+(y^2)/(225)=1 foci

\frac{x ^{2}}{289} + \frac{y ^{2}}{225} = 1

Frequently Asked Questions (FAQ)

What is the foci x^2+4y^2-64=0 ?
The foci x^2+4y^2-64=0 is (4sqrt(3),0),(-4sqrt(3),0)