What is the foci (x^2)/(289)+(y^2)/(225)=1 ?

The foci (x^2)/(289)+(y^2)/(225)=1 is (8,0),(-8,0)

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foci (x^2)/(289)+(y^2)/(225)=1

foci

\frac{x ^{2}}{289} + \frac{y ^{2}}{225} = 1

(8, 0), (- 8, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{289} + \frac{y ^{2}}{225} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 17, b = 15

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 7^{2} - 1 5^{2} : 8

(0 + 8, 0), (0 - 8, 0)

Refine

(8, 0), (- 8, 0)

4 x^{2} + y^{2} - 32 x + 4 y + 64 = 0

\frac{( x ) ^{2}}{144} + \frac{( y ) ^{2}}{169} = 1

\frac{( x + 3 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{9} = 1

2 x^{2} + 3 y^{2} + 4 x = 1

\frac{x ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

What is the foci (x^2)/(289)+(y^2)/(225)=1 ?
The foci (x^2)/(289)+(y^2)/(225)=1 is (8,0),(-8,0)