What is the foci ((x)^2)/(144)+((y)^2)/(169)=1 ?

The foci ((x)^2)/(144)+((y)^2)/(169)=1 is (0,5),(0,-5)

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foci ((x)^2)/(144)+((y)^2)/(169)=1

foci

\frac{( x ) ^{2}}{144} + \frac{( y ) ^{2}}{169} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 13, a = 12

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1 3^{2} - 1 2^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{( x + 3 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{9} = 1

2 x^{2} + 3 y^{2} + 4 x = 1

\frac{x ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{( x - 1 ) ^{2}}{25} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{576} + \frac{y ^{2}}{676} = 1

What is the foci ((x)^2)/(144)+((y)^2)/(169)=1 ?
The foci ((x)^2)/(144)+((y)^2)/(169)=1 is (0,5),(0,-5)