What is the foci (x^2)/(576)+(y^2)/(676)=1 ?

The foci (x^2)/(576)+(y^2)/(676)=1 is (0,10),(0,-10)

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foci (x^2)/(576)+(y^2)/(676)=1

foci

\frac{x ^{2}}{576} + \frac{y ^{2}}{676} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{576} + \frac{y ^{2}}{676} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 26, a = 24

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2 6^{2} - 2 4^{2} : 10

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

x^{2} + 3 y^{2} + 6 x + 6 = 0

16 x^{2} + 25 y^{2} - 48 x + 100 y - 264 = 0

9 x^{2} + 25 y^{2} + 54 x + 100 y - 44 = 0

15 x^{2} + 16 y^{2} = 240

\frac{( x - 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{4} = 1

What is the foci (x^2)/(576)+(y^2)/(676)=1 ?
The foci (x^2)/(576)+(y^2)/(676)=1 is (0,10),(0,-10)