What is the foci (x^2)/(100)+(y^2)/(16)=1 ?

The foci (x^2)/(100)+(y^2)/(16)=1 is (2sqrt(21),0),(-2sqrt(21),0)

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foci (x^2)/(100)+(y^2)/(16)=1

foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{16} = 1

(221, 0), (- 221, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 0^{2} - 4^{2} : 221

(0 + 221, 0), (0 - 221, 0)

Refine

(221, 0), (- 221, 0)

\frac{( x + 4 ) ^{2}}{5} + \frac{( y - 5 ) ^{2}}{9} = 1

\frac{x ^{2}}{1} + \frac{y ^{2}}{64} = 1

\frac{( x ) ^{2}}{13} + \frac{y ^{2}}{4} = 1

\frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{1 x ^{2}}{16} + \frac{y ^{2}}{9} = 1

What is the foci (x^2)/(100)+(y^2)/(16)=1 ?
The foci (x^2)/(100)+(y^2)/(16)=1 is (2sqrt(21),0),(-2sqrt(21),0)