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Popular >

foci (x^2)/(16/9)+(y^2)/(16)=1

Solution

foci

\frac{x ^{2}}{\frac{16}{9}} + \frac{y ^{2}}{16} = 1

Solution

(0, \frac{8 2}{3}), (0, - \frac{8 2}{3})

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{\frac{16}{9}} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = \frac{4}{3}

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} - (\frac{4}{3})^{2} : \frac{8 2}{3}

(0, 0 + \frac{8 2}{3}), (0, 0 - \frac{8 2}{3})

Refine

(0, \frac{8 2}{3}), (0, - \frac{8 2}{3})

Popular Examples

foci (x/5)^2+(y/3)^2=1 foci

(\frac{x}{5})^{2} + (\frac{y}{3})^{2} = 1

foci 9x^2+16y^2=1 foci

9 x^{2} + 16 y^{2} = 1

foci 4(x-4)^2+9y^2=36 foci

4 (x - 4)^{2} + 9 y^{2} = 36

foci ((x-1)^2)/(45)+((y-7)^2)/(81)=1 foci

\frac{( x - 1 ) ^{2}}{45} + \frac{( y - 7 ) ^{2}}{81} = 1

foci (x^2)/(67)+(y^2)/(57)=1 foci

\frac{x ^{2}}{67} + \frac{y ^{2}}{57} = 1

Frequently Asked Questions (FAQ)

What is the foci (x^2)/(16/9)+(y^2)/(16)=1 ?
The foci (x^2)/(16/9)+(y^2)/(16)=1 is (0,(8sqrt(2))/3),(0,-(8sqrt(2))/3)