What is the foci 2x^2+2y^2-28x+12y+114=0 ?

The foci 2x^2+2y^2-28x+12y+114=0 is (7,-3),(7,-3)

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foci 2x^2+2y^2-28x+12y+114=0

foci

2 x^{2} + 2 y^{2} - 28 x + 12 y + 114 = 0

(7, - 3), (7, - 3)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

2 x^{2} + 2 y^{2} - 28 x + 12 y + 114 = 0 :

Ellipse with center

(h, k) = (7, - 3), b = 1, a = 1

(7, - 3 + c), (7, - 3 - c)

Compute

c :

c = 1^{2} - 1^{2} : 0

(7, - 3 + 0), (7, - 3 - 0)

Refine

(7, - 3), (7, - 3)

25 x^{2} + 64 y^{2} = 1600

\frac{( x + 2 ) ^{2}}{22} + \frac{( y + 3 ) ^{2}}{18} = 1

25 (x + 2)^{2} + 4 (y - 3)^{2} = 100

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

16 x^{2} + 25 y^{2} - 224 x + 250 y = 191

What is the foci 2x^2+2y^2-28x+12y+114=0 ?
The foci 2x^2+2y^2-28x+12y+114=0 is (7,-3),(7,-3)