What is the center 4x^2+9y^2-16x+18y-11=0 ?

The center 4x^2+9y^2-16x+18y-11=0 is (2,-1)

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center 4x^2+9y^2-16x+18y-11=0

center

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

(2, - 1)

Solution steps

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

Rewrite

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), a = 3, b = 2

And the center is:

(2, - 1)

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

3 x^{2} + y^{2} - 24 x + 39 = 0

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{25} = 1

64 x^{2} + 100 y^{2} + 768 x - 600 y - 3196 = 0

What is the center 4x^2+9y^2-16x+18y-11=0 ?
The center 4x^2+9y^2-16x+18y-11=0 is (2,-1)