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Popular >

center 4x^2+y^2=1

Solution

center

4 x^{2} + y^{2} = 1

Solution

(0, 0)

Solution steps

4 x^{2} + y^{2} = 1

Rewrite

4 x^{2} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{1}{2}, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 1, a = \frac{1}{2}

And the center is:

(0, 0)

Popular Examples

center 16x^2+y^2=16 center

16 x^{2} + y^{2} = 16

center 3x^2+7y^2-12x-28y+19=0 center

3 x^{2} + 7 y^{2} - 12 x - 28 y + 19 = 0

center x^2+4y^2-6x+16y+21=0 center

x^{2} + 4 y^{2} - 6 x + 16 y + 21 = 0

center 5x^2+2y^2=50 center

5 x^{2} + 2 y^{2} = 50

center (x^2)/(63500)+(y^2)/(50900)=1 center

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

Frequently Asked Questions (FAQ)

What is the center 4x^2+y^2=1 ?
The center 4x^2+y^2=1 is (0,0)