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Popular >

center 4x^2+y^2=4

Solution

center

4 x^{2} + y^{2} = 4

Solution

(0, 0)

Solution steps

4 x^{2} + y^{2} = 4

Rewrite

4 x^{2} + y^{2} = 4

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

And the center is:

(0, 0)

Popular Examples

center ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 center

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

center 2x^2+2y^2+16y=0 center

2 x^{2} + 2 y^{2} + 16 y = 0

center x^2+9y^2+6x-90y+225=0 center

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

center 13x^2+49y^2=637 center

13 x^{2} + 49 y^{2} = 637

center (x^2)/(16)+(y^2)/(12)=1 center

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

Frequently Asked Questions (FAQ)

What is the center 4x^2+y^2=4 ?
The center 4x^2+y^2=4 is (0,0)