What is the eccentricity ((x^2))/(16)+((y^2))/(25)=1 ?

The eccentricity ((x^2))/(16)+((y^2))/(25)=1 is 3/5

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eccentricity ((x^2))/(16)+((y^2))/(25)=1

eccentricity

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{25} = 1

\frac{3}{5}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 4

= \frac{5 ^{2} - 4 ^{2}}{5}

\frac{5 ^{2} - 4 ^{2}}{5} = \frac{3}{5}

= \frac{3}{5}

\frac{x ^{2}}{36} + \frac{y ^{2}}{11} = 1

4 x^{2} + 32 x + 25 y^{2} - 250 y + 589 = 0

\frac{x ^{2}}{9} + \frac{( y + 5 ) ^{2}}{25} = 1

4 y^{2} + 9 x^{2} = 36

2 x^{2} + 3 y^{2} + 4 x = 1

What is the eccentricity ((x^2))/(16)+((y^2))/(25)=1 ?
The eccentricity ((x^2))/(16)+((y^2))/(25)=1 is 3/5