What is the eccentricity (x^2)/(16)+(y^2)/(81)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(81)=1 is (sqrt(65))/9

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eccentricity (x^2)/(16)+(y^2)/(81)=1

eccentricity

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1

\frac{65}{9}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 4

= \frac{9 ^{2} - 4 ^{2}}{9}

\frac{9 ^{2} - 4 ^{2}}{9} = \frac{65}{9}

= \frac{65}{9}

(y + 2)^{2} = 1 - 2 (x + 1)^{2}

\frac{x ^{2}}{5} + \frac{y ^{2}}{8} = 1

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

\frac{x ^{2}}{9} + y^{2} = 1

\frac{x ^{2}}{12} + \frac{y ^{2}}{49} = 1

What is the eccentricity (x^2)/(16)+(y^2)/(81)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(81)=1 is (sqrt(65))/9